For a body to be circumpolar, the body should always be above the rational horizon i.e the body should not set. Therefore, a circumpolar body will have upper transit (upper meridian passage) which is above the elevated pole and lower transit (lower meridian passage) which is below the elevated pole.
Condition required for a body to be circumpolar:
- Lat + Dec > 90° (For the body not to set)
- Latitude and declination should be the same name.
1. North Latitude – Lat < Dec
2. North Latitude – Lat > Dec
3. South Latitude – Lat < Dec
4. South Latitude – Lat > Dec
Upper and Lower transit of circumpolar bodies
Upper transit (NX) or (SX) of a circumpolar body is above the elevated pole.
For North latitudes,
Upper transit (NX) bearing is North, when lat < dec
= Altitude of pole + Polar distance (NP + PX)
= Latitude + Polar distance (Lat + PX)
= Declination circle + lower transit (XX’ + NX’)
= 90° – Zenith Distance (ZX)
Upper transit (SX) bearing is South, when lat > dec
= 180° – (Altitude of pole + Polar distance)
= 180° – (NP + PX) = 180° – (Latitude + Polar distance)
= 180° – (Lat + PX) = 180° – (Declination circle + lower transit)
= 180° – (XX’ + NX’)
For South latitudes,
Upper transit (SX) bearing is South, when lat < dec
= Altitude of pole + Polar distance (SP + PX)
= Latitude + Polar distance (Lat + PX)
= Declination circle + lower transit (XX’ + SX’)
= 90° – Zenith Distance (ZX)
Upper transit (NX) bearing is North, when lat > dec
= 180° – (Altitude of pole + Polar distance) = 180° – (SP + PX)
= 180° – (Latitude + Polar distance)= 180° – (Lat + PX)
= 180° – (Declination circle + lower transit) = 180° – (XX’ + SX’)
Lower transit (NX’ or SX’) is below the elevated pole.
For The North latitudes,
Lower transit (NX’) bearing is North, same as the elevated pole or latitude or declination.
= Altitude of pole – Polar distance (NP – PX’)
= Latitude – Polar distance (Lat – PX’)
= 90° – (PX’ + PZ)
For The South latitudes,
Lower transit (SX’) bearing is South, same as the elevated pole or latitude or declination.
= Altitude of pole – Polar distance (SP – PX’)
= Latitude – Polar distance (Lat – PX’)
= 90° – (PX’ + PZ)
If the altitudes of a circumpolar body at upper and lower meridian passage are observed,
– then the observer’s latitude and
– body’s declination can be calculated.
- Draw the rational horizon, place the body at the upper transit (X) and lower transit (X’)
- Place elevated pole midway between the 2 positions and draw declination circle, with the pole as the centre and the circle passing through X and X’.
- Draw equinoctial, WQE, where PQ is 90°
- Diameter of declination circle (XX’) = Upper altitude (NX) – lower altitude (NX’) (when Lower & Upper mer pass, brg is same)or= 180° – (Upper altitude (SX) + lower altitude (NX’)) (when Lower & Upper mer pass, brgs are opposite)
- The diameter, divided by 2 gives the polar distance PX and PX’.
(PX or PX’) = XX’ / 2
- Polar distance (PX) = altitude of the pole (NP) – lower meridian altitude (NX’)
- Polar distance (PX) = 90° – Declination
- 90° – polar distance (PX) = Declination, named same as elevated pole.
- Polar distance(PX) + lower meridian altitude (NX’)= Altitude of the pole (NP)
= Latitude of an observer, named same as the elevated pole.
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